write a C code to implement linear block codes

//write a C code to implement linear block codes



#include<stdio.h>
#include<conio.h>
void main()
{
inti,j,n,k,M[10],C[10],G[10][10],par[10][10];
clrscr();
printf(" For A Generator Matrix Enter :\n");
printf("1. The No Of Message Bits(n)\t: ");
scanf("%d",&n);
printf("2. The No Of Parity Bits(k)\t: ");
scanf("%d",&k);
printf("\nEnter The Elements Of Generator Matrix:\n");
for(i=0;i<k;i++)
for(j=0;j<n;j++)
scanf("%d",&G[i][j]);
printf("\nEnter The Message Bits\n");
for(i=0;i<k;i++)
scanf("%d",&M[i]);
printf("\t\t\tResult\n");
printf("____________________________________________________");
printf("\n\tThe Generator Matrix Is :\n\t");
for(i=0;i<k;i++)
{
for(j=0;j<n;j++)
printf("%d\t",G[i][j]);
printf("\n\t");
}
printf("\n\tThe Parity Matrix Is :\n\t");
for(i=0;i<k;i++)
{
for(j=0;j<n-k;j++)
{
par[i][j]=G[i][j+k];
printf("%d\t",par[i][j]);
}
printf("\n\t");
}
printf("\n\tTheMessege Bits :\n\t");
for(i=0;i<k;i++)
printf("%d ",M[i]);
printf("\n\n\tThe Parity Bits :");
for(i=0;i<n-k;i++)
{
C[i] = 0;
for(j=0;j<k;j++)
C[i]=(C[i] + M[j] * par[j][i])%2;
printf("\n\tC%d = %d",i+1,C[i]);
}
printf("\n\n\tCode Word For Given Messege Bit:\n\t");
for(i=0;i<k;i++)
printf("%d ",M[i]);
for(i=0;i<n-k;i++)
printf("%d ",C[i]);
printf("\n____________________________________________________");
getch();
}